A block of mass 2 kg, initially moving with velocity of 8 m/s on frictionless surface, collides with another block
of mass 2 kg resting on the edge of the surface having value of kinetic friction as 4 N. After collision the two
blocks stick and move together. Find the distance travelled by both the blocks before they come to rest.
Answers
Answered by
14
The FBD will be as
For equilibrium in vertical direction
N−mg=0
N=mg=(2)10=20 N
The normal contact force applied by the surface is 20 N, thus by Newton's third law of motion, 20 N force will be exerted by the block on the surface.
Option A is correct
Answered by
0
The FBD will be as
For equilibrium in vertical direction
N−mg=0
N=mg=(2)10=20 N
The normal contact force applied by the surface is 20 N, thus by Newton's third law of motion, 20 N force will be exerted by the block on the surface.
Option A is correct
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