Science, asked by kumariarumugam02, 6 months ago

A block of mass 2 kg, initially moving with velocity of 8 m/s on frictionless surface, collides with another block

of mass 2 kg resting on the edge of the surface having value of kinetic friction as 4 N. After collision the two

blocks stick and move together. Find the distance travelled by both the blocks before they come to rest.​

Answers

Answered by Anonymous
14

 \huge{ \underline{\underline{ \fcolorbox{white}{pink}{\sf{Answer :-}}}}}

The FBD will be as

For equilibrium in vertical direction

N−mg=0

N=mg=(2)10=20 N

The normal contact force applied by the surface is 20 N, thus by Newton's third law of motion, 20 N force will be exerted by the block on the surface.

Option A is correct

Answered by GoldenShaded
0

 \huge{ \:\:\:\:\:\:\:\:\:\:\underline{\underline{ \blue{ \bf{ Answer}}}}}

The FBD will be as

For equilibrium in vertical direction

N−mg=0

N=mg=(2)10=20 N

The normal contact force applied by the surface is 20 N, thus by Newton's third law of motion, 20 N force will be exerted by the block on the surface.

Option A is correct

Similar questions