Question

If cos²Q- sin²Q=½ than find the value of tan²Q​

Answer 1

Answer:

$\frac{1}{3}$

Step-by-step explanation:

cos²β - sin²β = $\frac{1}{2}$

cos²β - ( 1 - cos²β ) = $\frac{1}{2}$

2cos²β - 1 = $\frac{1}{2}$

cos²β = $\frac{3}{4}$

1 - sin²β = $\frac{3}{4}$ ⇒ sin²β = 1 - $\frac{3}{4}$ = $\frac{1}{4}$

tan²β = $\frac{1}{4}$ ÷ $\frac{3}{4}$ = $\frac{1}{3}$