A block of mass 2 kg is kept on a smooth horizontal surface and a force of 10N is applied in the rightward direction .the force acts for 5 second .find (a)Work done by this force ,(b)velocity of the body after 5seconds,(c)velocity of the body after 10seconds
Answers
Answer:
F = 10 N = Ma
1*a = 10N
a = 10 m/s^2
U = 0
T = 4 second
S = ut + 1/2at^2
S = 0 + 1/2(10)(16)
S = 80 m
So , work = FS
Work = 10*80= 800 Joules (answer)
Explanation:
A pressure of 10N acts on a frame of mass 1kg at rest for 10s and the body of mass 1kg at rest via a kinetic power K1 and . A force of 10N acts on a body of mass 1kg at relaxation via a distance of 10m and the body acquires a kinetic strength K1
In physics, a pressure is an influence which could alternate the movement of an object. A force can motive an object with mass to trade its pace (e.g. shifting from a nation of rest), i.e., to accelerate. force can also be defined intuitively as a push or a pull. A pressure has each significance and course, making it a vector amount. it's miles measured in the SI unit of newton (N). pressure is represented by means of the symbol F (formerly P).
The original form of Newton's 2d regulation states that the internet force appearing upon an item is equal to the rate at which its momentum modifications with time. If the mass of the object is steady, this law means that the acceleration of an item is directly proportional to the internet pressure performing at the item, is within the course of the internet pressure, and is inversely proportional to the mass of the object.
A block of mass 2 kg is kept on a smooth horizontal surface and a force of 10N is applied in the rightward direction .the force acts for 5 second
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