Question

A block of mass 2 kg is kept on
the floor. The coefficient of static
friction is 0.4. If a Force F of 2N
applied on the block as in
figure, the frictional force between the block and the floor will be
the block
(g= 10)
​

Answer 1

Answer:

hi

Step-by-step explanation:

Friction is a self adjusting force.

the max. value of it here is μmg = 0.4x20= 8 N

But since the applied force is less than 8N. So, the friction adjusts its value and new value becomes 2.8N so that block remains in equllibrium.

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