Question

A block of mass 2 kg is placed over smooth wedge of mass 4 kg as shown. Whole arrangement is made to accelerate with an unknown acceleration a, so that there is no relative motion between wedge and block Find net force acting on 2 kg block. (g = 10 m/s2)​

Answer 1

Answer:

F = mg

where, m = 2 kg, and gravity = 10 m/$s^{2}$

F = mg

F = 2 × 10

20 N

Explanation:

F = mg

where, m = 2 kg, and gravity = 10 m/$s^{2}$