a block of mass 2 kg moving at a speed of 10 M per second accelerates at 3 M per second square for 5 seconds calculate its final kinetic energy
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Answer is very simple that is 625
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First find final velocity
v = u + at
= 10 m/s + (3 m/s^2 × 5 s)
= 25 m/s
Final Kinetic energy = 0.5 × mass × (final velocity)^2
= 0.5 × 2 kg × (25 m/s)^2
= 625 Joule
Final kinetic energy of block is 625 Joule
v = u + at
= 10 m/s + (3 m/s^2 × 5 s)
= 25 m/s
Final Kinetic energy = 0.5 × mass × (final velocity)^2
= 0.5 × 2 kg × (25 m/s)^2
= 625 Joule
Final kinetic energy of block is 625 Joule
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