Question

A block of mass 2 kg placed on a frictionless surface. The flow of water is released at the rate of 1kg/s and the velocity of water jet is 5m/s. What is the initial acceleration of the block.

Answer pls..

Answer 1

The final velocity of mass of water after hitting the metal block is zero.

So the average change in momentum per sec = initial momentum

=

mass

×

initial velocity of water

=

1

k

g

×

5

m

/s

=

5

k

g

m

/s

As this change in momentum occurs during 1 sec. We may say that the force exerted on the 2kg metal block is

F

=

change in momentum

time

=

5

k

g

m

/s

1

s

=

5

N

Hence by Newton's law initial acceleration of the block of mass

m

=

2

k

g

is given by

a

=

F

m

=

5

N

2

k

g

=

2.5

m

/

s

2

Answer 2

Answer:

Hope my answer helps you.