a block of mass 2 kg placed on a long frictionless horizontal table is pulled horizontally by a constant force f it is found to move 10 m in the first 2 seconds find the magnitude of f
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☺ HERE IS YOUR ANSWER ☺
✔ ✔
m=2kg
s=10m
t=2 sec
acceleration =a
Initial velocity, u=0
s = ut + 1/2 at^2
10 = 1/2 a (4)
10 = 2a
a = 10/2 =5
so, From Newton's 2nd law of motion
F = ma
= 2×5
=10 N
HOPE IT'S HELP YOU ✌
❤ ❤
✔ ✔
m=2kg
s=10m
t=2 sec
acceleration =a
Initial velocity, u=0
s = ut + 1/2 at^2
10 = 1/2 a (4)
10 = 2a
a = 10/2 =5
so, From Newton's 2nd law of motion
F = ma
= 2×5
=10 N
HOPE IT'S HELP YOU ✌
❤ ❤
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