Question

A block of mass 2 m moving with a velocity of V collides with a block of mass 4m , which is at rest after collision first block comes into rest find the value of coefficient of restitution

Answer 1

Answer:

e=1

Explanation:

I hope this is helpful

Answer 2

Answer:

The value of coefficient of restitution is 0.25

Explanation:

Given;-

     Mass of lighter body = m

      Mass of heavier body = 2m

      Initial velocity of m = v

      Final velocity of m = 0

From the question, it is clear that the given case is of inelastic collision. Now, we know that, in an inelastic collision, for final velocity;

V₁ = (m₁ - em₂) u₁/ ( m₁ + m₂) + (1 + e) m₂u₂/ (m₁ + m₂)

where e represents coefficient of restitution.

So, putting the given values in the above formula, we obtain;-

    V = (m - e4m) v / ( m + 4m)

    0 = ( m - e4m) v / 5m

    0 = m - e4m

    m/4m = e

      e = 1/4

   e = 0.25

Hope it helps! ;-))