Question

A block of mass 20kg is pulled along a slope of 5m by mean of force 150N.by how much has potential energy of the block increased?? One who give right answer and explain me in simplest way I will give Him or her brainiest answer

Answer 1

Answer:

3mg( thrice of weight ) ( or 3 x 200 = 600 Joule }

Here, mgsinA = 120 => mg(3/5) = 120 =>mg = 200N. { A is the angle b/w 5m & 4m side }

Step-by-step explanation:

Let the block is initially placed at height a from the ground.

We know,

Potential energy of a body is dependent on the height of it from the zero-position. And it's defined by mgh. { where m is mass, g is gravitational acceleration and h is height from zero position }.

Hence, initial potential energy of that body is mg x a = > mga.

In that triangle, 5 & 4 are two numbers from a Pythagorean triplets, so the remaining should be length 3 m.

Now,

Potential energy of the body is mg( a + 3 ) = mga + mg3.

It's increased by ( mga + mg3 ) - mga = mg3.

Hope it helps

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