Question

A block of mass 250g slides down an inclined of inclination 37 degree with a uniform speed. find the work done against the friction as the block slides through 1 m

Answer 1

component of acceleration = g sin37 = 3g/5 = 6 m/s2
Force = ma
= 0.25 x 6 
= 1.5 N

work done= 1.5 x 1= 1.5 J

Answer 2

force=ma
=0.25×-6(hence frictional force is acting opposite
to it so a will be negative)
=-1.5

Thanks for asking help