Physics, asked by abhishek73846, 6 months ago

A block of mass 2kg is lying on a floor. the coefficient of kinetic friction is 0.54. What will be the value of frictional force if the applied force is 28N and g=10m/s^2​

Answers

Answered by MrkhiIadi
0

Answer:

As fms = μsmg = 0.4 × 2 × 10 = 8 N.

The applied force of 2.8 N is less than fms (= 8 N) and as such the block does not move. When the block is at rest,

frictional force = applied force = 2.8 N

Explanation:

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