A block of mass 2kg is placed on a horizontal road. Coefficient of friction between the block and the road is 0.2 If 6 N force act onthe block horizontally find the distance travelled by the lock in frist second.(g=10m/s^2)
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given that ,
》mass of block = 2kg
》force applied = 2.5
》coefficient of static friction, µs = 0.4
☆Maximum static frictional force,
fmax = µs × m × g = 0.4 × 2 × 9.8
=> fmax = 7.84 N
Since,
the applied force is less than the maximum static frictional force,
the frictional force on the block is equal to the applied force = 2.5 N.
☆it is due to the fact that static friction is a self adjusting force
nirmalsahasumouli:
In my question F= 6N, u=0.2. g=10m/s^2. And the question is the distance travelled by the block in first second
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