A block of mass 2kg moving at speed of 10m the acceleration at 3m /m2 for 5second compute its Final
kinetic energy
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Answered by
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u=10m/s
a= 3m/s^2
t= 5 sec
v=?
m= 2kg
KE=?
v= u+at
v= 10+3(5)
v= 25m/s
KE = 1/2mv^2
KE= 1/2x2x625
KE= 625J
a= 3m/s^2
t= 5 sec
v=?
m= 2kg
KE=?
v= u+at
v= 10+3(5)
v= 25m/s
KE = 1/2mv^2
KE= 1/2x2x625
KE= 625J
Answered by
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Velocity after 5s
v = u + at
v = 10 + (3 × 5)
v = 25 m/s
Final kinetic energy = 0.5mv^2
= 0.5 × 2kg × (25 m/s)^2
= 625 J
Final kinetic energy of block is 625 Joules
v = u + at
v = 10 + (3 × 5)
v = 25 m/s
Final kinetic energy = 0.5mv^2
= 0.5 × 2kg × (25 m/s)^2
= 625 J
Final kinetic energy of block is 625 Joules
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