Question

A block of mass 2kg moving with velocity collides with a block of mass 3kg at rest after collision the block move together . Find the loss of K.E in the collision?

Answer 1

∆K.E. is given by
$\frac{1}{2} u {v}^{2}$
where u is the reduced mass.
Thus the loss of KE becomes
$\frac{1}{2} \times \frac{5}{6} \times {v }^{2} \\ = \frac{5 {v}^{2} }{12}$