A block of mass 2kg rest on the floor of an elevator. which is moving down with acceleration 'g'. Then the apparent weight of the block is (take g=10m/s)
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35
Apparent weight of block = m(g - a)
= 2kg × (10 - 10) m/s^2
= 0 N
Apparent weight of the block in a lift moving downwards with acceleration equal to 10 m/s^2 is 0. It means there is no normal reaction between block and lift. Block will feel weightlessness.
= 2kg × (10 - 10) m/s^2
= 0 N
Apparent weight of the block in a lift moving downwards with acceleration equal to 10 m/s^2 is 0. It means there is no normal reaction between block and lift. Block will feel weightlessness.
Answered by
18
The weight will be 0....
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