Question

A block of mass 3 kg has a velocity of x ms. When a force of 18 N acts on the block, it reduces the velocity to
x2 ms after the block has covered a distance of 9 metres. Find the value of x​

Answer 1

Answer:

F = 18N

mass= 3kg

initial velocity = u m/s

final velocity = u/2 m/s

distance covered(S) = 9 m

F = 18N

ma = 18

3(a) = 18

a = 6 m/s^2

Now, from Newton equation

v^2 = u^2 + 2aS

u^2/4 = u^2 + 2(6)(9)

3u^2/4 = 108

u^2 = 108*4/3

u^2 = 144

u =12 m/s

pls mark brainiest