Question

a block of mass 37 kg rest on a rough horizontal plane having coefficient of static friction is 0.3 find out the force required to just move the block horizontally​

Answer 1

Here the normal reaction acting between the block and the plane is equal to the weight of the block. Hence,

R = mg = 37 × 9.8 = 362.6 N

So the static frictional force,

f = μR = 0.3 × 362.6 = 108.78 N

So we have to apply a force greater than 108.78 N to move the block.