Question

A block of mass 3kg has a velocity of um/s. When a force of 18N acts on the block, it reduces the velocity from U to U/2 after the block has covered a distance of 9 m. Find U?

Answer 1

Answer:

F = 18N

mass= 3kg

initial velocity = u m/s

final velocity = u/2 m/s

distance covered(S) = 9 m

F = 18N

ma = 18

3(a) = 18

a = 6 m/s^2

Now, from Newton equation

v^2 = u^2 + 2aS

u^2/4 = u^2 + 2(6)(9)

3u^2/4 = 108

u^2 = 108*4/3

u^2 = 144

u =12 m/s

Explanation:

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Answer 2

Explanation:

the answer is 12 ms^-1

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