Question

A block of mass 3kg has a velocity of um/s. When a force of 18N acts on the block, it reduces the velocity from U to U/2 after the block has covered a distance of 9 m. Find U?

Answer 1

Answer:

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Explanation:

mass = 3 kg, force= 18N

initial velocity= u m/ s

final velocity ,v = u/2 m/ s

As we know that F= ma

acc. to Newton's first law of motion...

F = ma

18 kg m/ s²=( 3kg )a. , a= 6 m/s²

As we know that v²- u² = 2as

S is given ie 9 m

V²- U²= 2AS

( U/2)² - U² = 2× 6 × 9

-3U²/4 = 108

-U² = 144

- U = +12 , -12

-U = -12

:......................................

: U= 12M/ S :::

:.....................................:

answer is

u = 12m/ s