A block of mass 3kg is kept on a rough horizontal surface of static friction 0.2 what is the minimum force needed to push it
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Minimum force required=friction constant*normal reaction
Therefore putting values in Formula
F=0.2*3*9.8
F=5.88N
therefore minimum force required=5.88 Newton
Therefore putting values in Formula
F=0.2*3*9.8
F=5.88N
therefore minimum force required=5.88 Newton
affanzafar:
bro its 5.88 N ! be brainly be precise!
i took g=10
sorry bro
no problem
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