A block of mass 3kg is placed on the horizontal surface of truck (0.5) and the truck is moving
with an acceleration 2 m/s2
. The frictional force on the block will be (g = 10 m/s2
)
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Explanation:
Mass(m) =3 kg
Acceleration (a) =2m/s^2
Pseudo force will be act on the block in opposite direction of acceleration which is equal to
F=3×2=6N
f=F=6N ans
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