Question

satellite of mass M and 2m are revolving in two circular orbit of radius R and 2r around an imaginary planet on the surface of with gravitational force is inversely inversely proportional to distance from its Centre the ratio of Orbital speed of satellite is

Answer 1

Answer:

from the figure, centripetal force,

f=

r

mv

2

v

2

=

m

fr

The orbital speed of 1st satellite is

v

1

=

m

fr

. . . .(1)

The orbital speed of 2nd satellite,

v

2

=

2m

f2r

v

2

=

m

fr

. . . . .(2)

Ratio v

1

:v

2

=1:1

Explanation:

from the figure, centripetal force,

f=

r

mv

2

v

2

=

m

fr

The orbital speed of 1st satellite is

v

1

=

m

fr

. . . .(1)

The orbital speed of 2nd satellite,

v

2

=

2m

f2r

v

2

=

m

fr

. . . . .(2)

Ratio v

1

:v

2

=1:1