A block.Of mass 4 kg is placed on a rough inckined surface as shown . The minimum force f which is parallel to inclined to keep the block at rest is
Answers
Answer: just a example to do it..........
Explanation:
he upward force is given by
A block of mass m is placed on a plane inclined at an angle θ to the horizontal. It is pulled upwards by a force f. The weight mg of the block acts vertically down wards. The reaction R acts upwards, perpendicular to the inclined plane. the force of friction F acts downwards along the plane. This is shown in the diagram attached.
The weight mg is resolved into 2 components- mg cosθ perpendicular to the plane and mg sinθ downwards along the plane.
The force f just makes the block move up the plane, hence the block is in static equilibrium.
Apply the condition for equilibrium in a direction parallel to the plane.
Apply the condition for equilibrium perpendicular to the plane.
The friction is related to reaction force as follows:
Substitute equation (2) and (3) in equation (1).
Thus, the force needed to just pull the block upwards is
Answer:
2gsin2Θ
Explanation:
