Question

a block of mass 4 kg is placed on a smooth surface . another block of mass 2 kg is placed over it the coefficient of friction between the two blocks is u= 0.5 . A force of 12 N is applied at the lower block as shown the force of friction between the blocks is



options
1.8 N
2.6N
3.4N
4.10N​

Answer 1

Answer:

In the first case, friction acts only between the 4kg block and the 5kg block.

As a result if 12N is the force required for both the blocks to move together,

In the second case, we consider both the blocks as a system and the force acting between them is an internal force.

Thus the ratio of the forces applied on a block to the mass of the block should be a constant.

4

12

​  

=  

9

F

​  

 

Hence, the maximum force F = 27 N

Explanation:

Answer 2

Answer:

hiii

Explanation:

sameas given in above ans