Question

A block of mass 4 kg is resting on a frictionless plane. It struck by a jet releasing water at 2 kg/s and at a speed 10 m/s. Find initial acceleration of the block

Answer 1

The final velocity of mass of water after hitting the metal block is zero.

So the average change in momentum per sec = initial momentum

=

mass

×

initial velocity of water

=

1

k

g

×

5

m

/s

=

5

k

g

m

/s

As this change in momentum occurs during 1 sec. We may say that the force exerted on the 2kg metal block is

F

=

change in momentum

time

=

5

k

g

m

/s

1

s

=

5

N

Hence by Newton's law initial acceleration of the block of mass

m

=

2

k

g

is given by

a

=

F

m

=

5

N

2

k

g

=

2.5

m

/

s

2

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