Question

A block of mass 4kg falls from height of 3m on a spring of force constant 1500n/m calculate max compression of spring

Answer 1

Answer: x = 0.4 m

Explanation:

The potential energy stored in the block coverts to the elastic potential energy of the spring which causes compression.

$mgh=\frac{1}{2}kx^2$

where, m is the mass of the block, g is the acceleration due to gravity, k is the spring constant, h is the height from which the block falls and x is the maximum compression of the spring.

It is given that,

mass, $m=4 kg$

height, $h=3 m$

spring constant, $k= 1500 N/m$

acceleration due to gravity, $g=9.8 m/s^2$

$\Rightarrow x= \sqrt{\frac{2mgh}{k}}\\ \Rightarrow x= \sqrt{\frac{2\times 4 kg\times 9.8 m/s^2 \times 3m}{1500 N/m}}=\sqrt{0.1568}=0.4 m$

Hence, the max compression of spring is 0.4 m

Answer 2

Therefore the answer is 0.39

Hope it helps you