A block of mass 5 kg is at rest on smooth horizontal surface.Watercomingoutof a pipe horizontally at the rate of 2 kgs-1 hits the block with a velocity of 6ms-1. The initial acceleration of the block is
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Answer:
(12/5) m/s²
Explanation:
The force exerted by the water jet,
F = v(dm/dt) = (6m/s)(2kg/s) = 12kgm/s²
We know, F = ma => a = F/m = (12kgm/s²)/5kg = (12/5) m/s²
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