A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case (B), by a force F = 20 N, making an angle of 30º with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is m = 0.2. The difference between the accelerations of the block, in case (B) and case (A) will be : (g = 10 ms⁻²)
(A) 0.4 ms⁻²
(B) 3.2 ms⁻²
(C) 0 ms⁻²
(D) 0.8 ms⁻²
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Option A is correct.... ❤
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Answer: let first find the individual acceleration for two cases :
a.) Case 1 : object is pushed
Here, Normal reaction is ,
[ 50 + {20sin(30°)}] = 60N
Friction force is = 60×0.2 = 12N
Pushing force in direction of motion is, 20cos(30°) = 10√3 N = 17.32 N
Net acc. = [ 17.32 - 12 ]/5
= 1.064m/s^2
Case 2 : object is pulled
Normal reaction = 50 - 20sin(30°)
= 40N
Friction force = 0.2× 40 = 8N
Pulling force in direction of motion
= 10cos30° = 17.32N
Net acc. = [17.32 - 8 ]/5 = 1.864m/s^2
So, difference in acceleration is
= 1.864 - 1.064 = 0.8m/s^2
Option d is correct.
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