Question

A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5 N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting?

Options

(a) 6 m
(b) 8 m
(c) 10 m
(d) 2 m

Answer 1

Answer:

Step-by-step explanation:

Assume initial velocity of 1.5 m/s is in the x-direction

Since there are no forces on it in this direction, there will be no acceleration. So distance = s(x) = 1.5 m/s (4 sec) = 6 meters

In the y-direction, F=5N and since m=5 kg, Newton's 2nd Law tells us acceleration a(y) = F/m = 5/5 = 1 N/kg = 1m

s2s(y) = 12a(y)t2=12(1)(42)=8meters

Resolving the x and y vector, we note the Pythagorean Triple of 6, 8, 10. So the distance travelled is 10 meters.

Answer 2

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