Question

A block of mass 5 kg is moving with A speed of 8m/s along east .If the force of 10 N is applied on it for 3 s along north ,then the final speed of the block will be

Answer 1

Answer:

M=5kg

Force=lo

initial velocity=8m/s

time=3s

put the value of force,

F=ma

lo=5×(v-8)/3

lo=-4ov/3

lo×3=-4ov

3o=-4ov

v=-4o/3o

v=-l.3m/s