Question

plzz give me answer okkkkkkkkk

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Dear student,

# Answer- a1 + a6 + a11 + a16

# Explaination-

Consider an arithmetic progression with first term a1 and common difference d.

Then nth term is given by

an = a1 + (n-1)d

# Given is,

a1 + a4 + a7 + a10 + a13 + a16 = 147

a1 + a1+3d + a1+6d + a1+9d + a1+12d + a1+15d = 147

6a1 + 45d = 147

2a1 + 15d = 49 ...(1)

# Ti find,

a1 + a6 + a11 + a16 = x

a1 + a1+5d + a1+10d + a1+15d = x

4a1 + 30d = x

2 (2a1 + 15d) = x

2 × 49 = x

x = 98

Hence, a1 + a6 + a11 + a16 = 98.

Keep asking.