Question

a block of mass 5 kg is placed on a rough table. the coefficient of static and kinetic friction between surfaces of block and table be 0.4 and 0.3 respectively. if the force F exerted on the block is 10N (g=10m/s^2) the force of friction between the block and the table is ------------------.

explain briefly.

Answer 1

mass of block = 5 kg
coefficient of static friction, $\mu_s$ = 0.4
coefficient of kinetic friction $\mu_k$= 0.3

limiting friction = $\mu_s$×m×g=0.4×5×10 = 20N

Until a force greater than 20N is applied, the block won't move. For any force F ≤ limiting friction, the value of friction will be F since friction is a self-adjusting force.

So when a force 10N is applied, the friction between block and table is 10N.

Answer 2

Answer:

mass of block = 5 kg

coefficient of static friction,

$\mu_s$

= 0.4

coefficient of kinetic friction

$\mu_k$

= 0.3

limiting friction =

$\mu_s$

×m×g=0.4×5×10 = 20N

Until a force greater than 20N is applied, the block won't move. For any force F ≤ limiting friction, the value of friction will be F since friction is a self-adjusting force.

So when a force 10N is applied, the friction between block and table is 10N.