A block of mass 6 kg is lowered with the help of a rope of negligible mass through a distance of 20 m with an acceleration of 1.96 meters second square work done by the rope on the block is
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Answered by
3
Answer:235.2J
Explanation:
Work done= F×s
F=ma
=6×1.96
=11.76
W=F×S
=11.76×20
=235.2J
Answered by
3
Given:
Mass of the block = 6kg
Mass of the rope = 20m
Acceleration = 1.96m
To Find:
Square work done on the rope.
Solution:
Work done = F = ma
= 6 × 1.96
= 11.76
To calculate square work done -
W = f × s
= 11.76 × 20
= 235.2
Answer: The work done is 235.2J
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