Question

a block of mass 8 kg is pulled along a horizontal frictionless surface by a rope of mass 2 kg with a force of hundred newton is applied at the free end of the Rope find the force exerted by the rope on the block​

Answer 1

Hey here is your answer

Here let N be the force applied by rope on the block which is same as the force applied by block on rope

So , a= Fnet/Mnet = 100/(8+2) = 10 m/s^2

the only force acting on block is N i.e the force exerted by rope

so eq becomes

N= ma = 8*10 = 80 N

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Answer 2

Answer:

Consider the block + rope as a system and calculate the acceleration of the whole system by using F=ma

$⇒a⇒1008+2=10m/s2$

now consider block and rope as individual system as shown in figure

for the rope we can write

$</p><p> F−N=2a100−N= 2×10N=80 NOR for  \: the  \: block \:  we \:  can \:  write \:  N=8aN=8×10=80 N$