A block of mass Ikg is placed on the door. The coefficient of static
friction is 0.2.If a force of IN is applied on the block, the force of friction
(a)
(b) 2N (C) IN (d) Varies with the area of contact of the block
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force of friction = u r
r= mg ....
so ...f = umg
f= 0.2 ×1×10
f= 2N
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