A block of mass m=0.1kg is released from a height of 4m on a curved smooth surface. On the horizontal path
Answers
Answered by
29
The question is incomplete.
However,
Given:
- Mass = 0.1 kg
- Height = 4 m
- Length of the path AB = 1 cm
- Length of the path BC = 2 cm
- Perfectly elastic
Solution:
The total distance covered by the block on the horizontal surface before coming to rest can be given by,
mgh = μmgd
d = h/μ = 4/01
d = 40 m
Number of times, n = 40/2 = 20 times.
- BC 20 times
- AB 19 times
Distance = 20(2)+19(1) = 59 m
Hence, the distance is 59 m.
Answered by
0
Answer:
59 m
Explanation:
Given:
Mass = 0.1 kg
Height = 4 m
Length of the path AB = 1 cm
Length of the path BC = 2 cm
Perfectly elastic
Solution:
The total distance covered by the block on the horizontal surface before coming to rest can be given by,
mgh = μmgd
d = h/μ = 4/01
d = 40 m
Number of times, n = 40/2 = 20 times.
BC 20 times
AB 19 times
Distance = 20(2)+19(1) = 59 m
Hence, the distance is 59 m.
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