Question

A block of mass m = 2.0 kg was dropped from height h onto a spring of spring constant k = 1960 N/m. The maximum distance the spring was compressed was 0.05 m. Find the height h from which the block was dropped.
plz give me answer urgently!​

Answer 1

Answer:

ANSWER

Given data,

Mass of the body is ( m ) =2Kg

spring's constant (K)=1960N/m

height of the body =0.4m

Let the maximum distance spring will compressed =xm

initial potential energy of body =mg(h+x)

final potential energy = spring potential energy =

2

1

Kx

2

according to the law of conservation of energy,

initial potential energy = final potential energy

mg(h+x)=

2

1

Kx

2

2mgh+2mgx=Kx

2

Kx

2

−2mgx−2mgh=0

⇒1960x

2

−2×2×9.8×x−2×2×9.8×0.4=0

⇒1960x

2

−39.2x−15.68=0

after solving this quadratic equations , we get x=0.1m

hence, answer is x=0.1m

Answer 2

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