An airplane is resting on the runway. Its normal takeoff speed is 360 m/s. If it can generate a maximum acceleration of 20 find the minimum time in which it can take off?
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Answer:
[ v = u + at ; t = v - u /a ]
time = final velocity - initial velocity / acceleration
= 360 m/s - 0 / 20 m/s^2
= 18 seconds
hope it helps you
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