Question

A block of mass m is lowered with the help of a rope of negligible mass through a distance d with acceleration of g/3. Find the work done by the rope on the block​

Answer 1

Answer:

Explanation:

According to the given problem

During lowering a block , tension in rope is

T = m(g-a) and

S = d

Work done W = -m (g-a)d

W = -m (g - g/3)d

= - 2mgd/3

Answer 2

$- \frac{2mgd}{3}$ is the work done by the rope of the block.

Explanation:

Tension and acceleration work on the block due to gravity. So that:

ma = T - mg

m(g - a) = T

m( g/3 - g) = T

= -2mg/3

As we know that,

Work Done = force * displacement

= $\frac{-2mg}{3} d$

Therefore, the work done by the rope on the block;

= $- \frac{2mgd}{3}$

Learn more: calculate the work done

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