a block of mass m is lying at the bottom of a smooth inclined plane . Force F1 and F2 are actung on the block as shown in the figure the block is moved to the top of inclined plane with constant speed. the net work done by the force F1 and F2
Answers
Answered by
1
Explanation:
Hint: Work done by all forces is equal to change in kinetic energy.
Sol.: Work done by forces + work done by gravity = ΔK = 0
work done by
work done by = mgh
Hope it helps....✌️✌️✌️
pls mark as brainliest!!!!!!!!!!!!!!!!
Similar questions