Question

A block of mass m is moving with speed v on a wedge of mass M which is placed upon a horizontal surface.
Track AB is a circular track of radius R. What is the minimum speed v, so that the block reaches point A
(All surfaces are frictionless)?

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Answer 1

Answer: $v =\sqrt{\frac{2gR}{\frac{M}{M+m} } }$

Explanation:First conserve the momentum and then conserve the energy as attached in the image.

Let v and $v^{'}$ e the velocities are at the starting time and at the top position respectively.