x-2y + 3z = 0
3x + 3y = 0
x + z = 0
solve the equation. find the value of x,y,z
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1
Answer:
X=0
Y=0
Z=0
Step-by-step explanation:
3x+3y=0
x+z=0)X3
--------------------
3y-3z=0
(y-z=0)____(eq.1)
it means
*y=z*
putting in(x-2y+3z=0)
x-2z+3z=0
(x+z=0)
OR
(x+y=0)
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