A block of mass m is placed in contact with another block of mass M
as shown in the figure. The coefficient of friction between the blocks
is p = 0.5. With what acceleration the block M should move so that
the block m does not slide down ? There is no friction between the
ground and block of mass M.
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Answered by
11
Answer:
Explanation:
If the cart acceleration with ′α′
Pseudo force on mass F=mα
Force of friction =μN
For horizontal equilibrium F=N
f=μmα
The block will not fall as long as f≥mg
μmα≥mg
α≥g/μ
Hence d is the correct answer.
Answered by
1
Answer:
Answer :
d
Solution :
Here the force applied should be such that friction force acting on the upper block ofshould not be more than the limiting frictionlet the system moves with acceleration a Then for whole system <br>...(i) <br> For block of m.<br>...(ii) <br> From Eqs (i) and (ii) we get br
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