Question

A block of mass M is placed on a rough inclined plane

having angle of inclination 450

. The coefficient of

friction is 0.5. What is the acceleration of the block

down the inclined plane? Acceleration due to gravity is

g:

(a) 0.20 g (b) 0.25 g

(c) 0.30 g (d) 0.35 g​

Answer 1

Answer:

d 0.35

Explanation:

Draw a diagram for same

with Mass m inclined to 45°

then the weight acting downward is mg

but for inclined line its mg•cos45° with adding friction it is mue•m•g•cos45° = 0.3535

Answer 2

The acceleration of the block  down the inclined plane is 0.20g

Option a is correct

Explanation:

Free body diagram in attachment.

A block of mass M is placed on a rough inclined plane having angle 45°

Friction force, $f_c=\mu mg$

where, $\mu = 0.5$

Force under gravity, $f_g=mg$

Component of gravity force,

Force along surface, $f_s=mg\sin45^\circ$

Block is down by inclined plane.

Let acceleration of block is a

Therefore, the equilibrium equation,

$ma=mg\sin45^\circ-\mu mg$

$a=g(\sin45^\circ-0.5)$

$a=0.2g$

hence, the acceleration of block is 0.20g

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