A block of mass m is placed on a smooth inclined plane of angle θ. The normal force exerted by the surface of the plane would be ............... .
(A) mg
(B) mg/cosθ
(C) mg cosθ
(D) mg sinθ
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0
Answer: mgcos|
Explanation:
Answered by
4
Answer:
(C) mg cosθ
Explanation:
As given in question,
mass of block = m
angle of inclination = I
let's draw the free body diagram with the given information. The figure should be as shown in figure.
There will be downwards force on the block due to force of gravity and there is a normal force on the block normal to the plane. In equilibrium condition the component of force due to gravity will balance this normal force. So,
normal force, N = mg cosÎ
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