Question

A block of mass M is pulled along a horizontal friction less surface by a rope of mass m. A horizontal force F is applied to one end of the rope. Find 1) The acceleration of the rope and block. 2) The force that the rope exerts on the block. 3) Tensionin the rope at its mid point??

Answer 1

$\textbf{Answer...}$

1) Acceleration a = F/(m+M)

2) Force exerted by rope T = Ma = M.F/(m+M)

3) T1 = (m/2+M)a = [m+2M/2] [ F/m+M ]

Tension in rope at mid point T1 = (m+2M)F/2(m+M)

Hope it helps u✌

Answer 2

Here is your answer:

》》By the above information

1) Acceleration= F/m+M

2)The force that exerts =
M(F/m+M)

=>m/2+M.a

= (m+2M/2)(F/m+M)

3)Tension in rope at mid point is

=m+2M.F/2(m+M).


Hope you understand..☆☆