Physics, asked by MiniDoraemon, 8 months ago

A block of mass M is pulled along a horizontal frictionless surface by a tope of mass m . if a force p is applied st the free end of the roof , the force exerted by the rope on the block is [AIEEE 2003] ​

Answers

Answered by Anonymous
0

Explanation:

ANSWER

Consider the system as a whole

A block of mass M and a rope tied to it of mass m pulled by a force P,

The only external force

The system will accelerate due to the action of the force , all accelerating with same acceleration

Acceleration of the system =

Totalmass

Totalexternalforce

a =

m+M

P

Therefore acceleration of the block of mass M will also be a

Net force on it = mass x acceleration

This force is force of the rope on the block

Hence F =

m+M

PM

Answered by TheLifeRacer
1
  • Explanation:- Let acceleration of system ( rope + block ) be a along the direction of applied force . then ,
  • a = P/M +m

Then draw FBD of block and root as shown in figure .

Where , T is the required parameter

  • For block , T = ma
  • ⟹T = Mp/M+m

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