A block of mass M is pulled along a horizontal frictionless surface by a tope of mass m . if a force p is applied st the free end of the roof , the force exerted by the rope on the block is [AIEEE 2003]
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Explanation:
ANSWER
Consider the system as a whole
A block of mass M and a rope tied to it of mass m pulled by a force P,
The only external force
The system will accelerate due to the action of the force , all accelerating with same acceleration
Acceleration of the system =
Totalmass
Totalexternalforce
a =
m+M
P
Therefore acceleration of the block of mass M will also be a
Net force on it = mass x acceleration
This force is force of the rope on the block
Hence F =
m+M
PM
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- Explanation:- Let acceleration of system ( rope + block ) be a along the direction of applied force . then ,
- a = P/M +m
Then draw FBD of block and root as shown in figure .
Where , T is the required parameter
- For block , T = ma
- ⟹T = Mp/M+m
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