a block of mass m is released on the top smooth inclined plane
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f=¥R=¥mg cos¢
where f is friction force
¥ is coefficient of friction
m is mass
g is acceleration due to gravity
the another force opposite to friction force is
F=mg sin¢
: mg sin¢=mg ¥ cos¢
¥=tan¢
where f is friction force
¥ is coefficient of friction
m is mass
g is acceleration due to gravity
the another force opposite to friction force is
F=mg sin¢
: mg sin¢=mg ¥ cos¢
¥=tan¢
Answered by
0
mass =m
distance covered =x
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