Math, asked by sidpatwal, 1 year ago

Prove that sec8x-1/sec4x-1=tan8x/tan2x

Answers

Answered by 7255987278
2
sec 8x-1/sec4x-1= 1- cos8x/cos8x ×1-cos4x/cos4x
=2sin²4x/cos8x × 2sin²2x/cos 4x
=

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